What happens when ethyl chloride is treated with sodium iodide in presence of acetone?
Answers
Answer:
ethyl iodide is formed.
CH3CH2CL+NaI in presence of acetone CH3CH2I+NaCL
When ethyl chloride is treated with sodium iodide in the presence of acetone, it undergoes a nucleophilic substitution reaction known as the Finkelstein reaction.
When ethyl chloride is treated with sodium iodide in the presence of acetone, it undergoes a nucleophilic substitution reaction known as the Finkelstein reaction.
In this reaction, the iodide ion (I-) from sodium iodide replaces the chloride ion (Cl-) in ethyl chloride, forming ethyl iodide and sodium chloride as byproduct:
C2H5Cl + NaI → C2H5I + NaCl
The presence of acetone in the reaction mixture serves as a solvent and also helps to prevent the formation of undesirable side products.
Overall, the Finkelstein reaction is a useful method for converting alkyl chlorides to alkyl iodides, which can be useful intermediates in various organic synthesis reactions.
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