Chemistry, asked by ayushsaxena350599, 16 days ago

What happens when :-

i) A copper vessel is exposed to moist air for a long time.
ii) Magnesium reacts with oxygen.
iii) Sulphur dioxide is dissolved in water.​

Answers

Answered by shettysachi5
2

Answer:

i) When a copper vessel is exposed to moist air for an extended time it develops a green layer on its surface. Copper corrodes by oxidation during which it reacts with oxygen within the air to make oxide. ... The green material may be a mixture of copper hydroxide (Cu(OH)2) and copper carbonate (CuCO3).

ii) When magnesium reacts with oxygen, it produces light bright enough to blind you temporarily. Magnesium burns so bright because the reaction releases a lot of heat. As a result of this exothermic reaction, magnesium gives two electrons to oxygen, forming powdery magnesium oxide (MgO

iii) The reaction of Sulphur dioxide with water leads to the formation of acid called Sulfurous acid. ... When the gas is dissolved in water, it yields an acid called sulfurous acid with chemical formula as shown in the chemical equation: Sulfurous acid is a good reducing agent with molar mass 82.07g/mol

Explanation:

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Answered by techiegaru2
1

Answer:

i)When copper vessel is exposed to moist air for a long time it develops a green layer on its surface. Copper corrodes by oxidation in which it reacts with oxygen in the air to form copper oxide. Copper oxide then combines with carbon dioxide to make copper carbonate, which gives it a green colour.

ii)When magnesium reacts with oxygen, it produces light bright enough to blind you temporarily. Magnesium burns so bright because the reaction releases a lot of heat.

iii)When sulphur dioxide is dissolved in water it forms sulphurous acid

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