Question

What happens when
(i) White phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO₂.
(ii) XeF₆ undergoes partial hydrolysis.
(Give the chemical equations involved).

Answer 1

(i) when white phosphorus is heated with concentrated sodium hydroxide {e.g., NaOH} solution in inert atmosphere of carbon dioxide, phosphorus undergoes $\textbf{disproportionation}$ reaction to form phosphine has { e.g., PH3}

chemical equation of reaction between white phosphorus and concentrated sodium hydroxide is given below :
$P_4+3NaOH+3H_2O\rightarrow PH_3+3NaH_2PO_2$

(ii) when Xenon hexafluoride {e.g., XeF6} undergoes partial hydrolysis, xenon hexafluoride gives Xenon oxyfluoride {e.g., XeOF4} and hydrogen fluoride {e.g., HF}

chemical equation of partial hydrolysis of XeF6 is given below :
$XeF_6+H_2O\rightarrow XeOF_4+2HF$

Answer 2

when white phosphorus is allowed to be heated with concentrated sodium hydroxide {e.g., NaOH} solution in inert atmosphere of carbon dioxide, phosphorus undergoes disproportionation reaction to form phosphine gas { e.g., PH3}

(ii) when Xenon hexafluoride {e.g., XeF6} undergoes partial hydrolysis, xenon hexafluoride gives Xenon oxyfluoride {e.g., XeOF4} and hydrogen fluoride {e.g., HF} as the products.

chemical equation of partial hydrolysis of XeF6 is given below :

XeF6 +H2O=XeOF4+HF