What happens when mass or velocity in kinetic energy is doubled or half of an object?
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If both are doubled
M = 2 m
V = 2v
So k.e = 0.5 mv2
= 0.5× 2m × (2v) 2
= 0.5 ×2 m × 4v2
= 0.5 m × v2 × 2×4
K.e = k.e 8
Means kinetic energy will be 8 times then the first kinetic energy. ...
When both are half
M = 0.5 m
V = 0.5v
So k.e = 0.5 mv2
= 0.5× 0.5m × (0.5v) 2
= 0.5 × 0.5 m × 0.25 v2
= 0.5 m × v2 × 0.5 × 0.25
K.e = ke 0.125
Means kinetic energy is 0.125 times the original kinetic energy. ...
Hope it helps you ...
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M = 2 m
V = 2v
So k.e = 0.5 mv2
= 0.5× 2m × (2v) 2
= 0.5 ×2 m × 4v2
= 0.5 m × v2 × 2×4
K.e = k.e 8
Means kinetic energy will be 8 times then the first kinetic energy. ...
When both are half
M = 0.5 m
V = 0.5v
So k.e = 0.5 mv2
= 0.5× 0.5m × (0.5v) 2
= 0.5 × 0.5 m × 0.25 v2
= 0.5 m × v2 × 0.5 × 0.25
K.e = ke 0.125
Means kinetic energy is 0.125 times the original kinetic energy. ...
Hope it helps you ...
Mark me as brainlist if it is useful to you
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