what happens when MgSO4 ,7H2O is heated ? Write the appropriate equation
Answers
Answer:
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Explanation:
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Explanation:
Let the mixture is X% by mass of CuSO
4
.5H
2
O and 100 - X % by mass of MgSO
4
.7H
2
O. 5.0 g of mixture will contain 0.05X g CuSO
4
.5H
2
O and 5.0 - 0.05X g MgSO
4
.7H
2
O
The molar masses of CuSO
4
.5H
2
O and MgSO
4
.7H
2
O are 249.7 g/mol and 246.5 g/mol respectively.
The number of moles of CuSO
4
.5H
2
O=
249.7
0.05X
=2.00×10
−4
X moles.
The number of moles of MgSO
4
.7H
2
O=
246.5
5.0−0.05X
Total number of moles of water obtained =5×2.00×10
−4
X+7×
246.5
5.0−0.05X
=1.00×10
−3
X+
35.22
5.0−0.05X
Mass of water obtained =5.0−3.0=2.0 g
Moles of water obtained =
18
2.0
=0.11111
Hence,
1.00×10
−3
X+
35.22
5.0−0.05X
=0.11111
3.522×10
−2
X+5.0−0.05X=3.9133
0.01478X=1.0867
X=74.4 %
Hence, the percentage by mass of CuSO
4
.5H
2
O in the original mixture was 74.4 %