What happens when n butyl bromide is treated with alcoholic koh?
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Answer: When n butyl bromide is treated with alcoholic KOH then it shows dehydration or beta-elimination reaction in the OH and hydrogen will be removed from the beta position of the carbon and form alkene as main product and KBr and water as bi-product.
Ch₃-Ch₂-Ch₂-Ch₂ + KOH(alc.) ⇒ Ch₃-Ch₂-Ch=Ch₂ + KBr + H₂O
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action of alcoholic KOH on n- butyl bromide
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