Chemistry, asked by devgunananya, 1 year ago

what happens when propanoic acid is warmed with methanol in the presence of concentrated sulphuric acid write equation for the reaction

Answers

Answered by kukadiakrishnaa
3

when propanoic acid is warmed up with methanol in the presence of concentrated sulphuric acid esterification takes place and an ester named methyl propanoate is formed along with water

equation is:

C2H5COOH + CH3OH ----> C2H5COOCH3 +H20


devgunananya: Thank you so much.
kukadiakrishnaa: my pleasure
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