what happens when propanoic acid is warmed with methanol in the presence of concentrated sulphuric acid write equation for the reaction
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when propanoic acid is warmed up with methanol in the presence of concentrated sulphuric acid esterification takes place and an ester named methyl propanoate is formed along with water
equation is:
C2H5COOH + CH3OH ----> C2H5COOCH3 +H20
devgunananya:
Thank you so much.
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