Question

What happens when the gas obtained by heating methanoic acid and conc.H2SO4 is passed through heated ferric oxide

Answer 1

Answer:

At first you need to know what happens when the first 2 products are heated, only then you can know what gasses pass trough the NaOH solution.

And that is: The weak and hydrated oxalic acid gets dehydrated& decomposed:

(COOH)2. 2H2O + conc. H2SO4 + heat→ CO(gas) + CO2(gas) + [H2SO4.3H2O]

then these gasses pass trough the NaOH solution:

Co pass-trough since it is not absorbed or reacting with the hydroxide,

but CO2 gets absorbed & reacts & becomes Na2CO3.

Answer 2

Answer:

The gas obtained by heating methanoic acid (HCOOH) and concentrated sulfuric acid (H2SO4) is passed through heated ferric oxide (Fe2O3).

Explanation:

From the above question,

When the gasoline got by way of heating methanoic acid (HCOOH) and centred sulfuric acid (H2SO4) (known as carbon monoxide or CO) is handed thru heated ferric oxide (Fe2O3), it reacts with the Fe2O3 to produce iron (II) oxide (FeO) and carbon dioxide (CO2) as follows:

            2CO + Fe2O3 → 2FeO + 3CO2

This response is an instance of a redox reaction, the place one substance (Fe2O3) is decreased and every other (CO) is oxidized.

In this case, Fe2O3 is decreased to FeO by way of gaining electrons from CO, which is oxidized to CO2 through dropping electrons to Fe2O3.

The ensuing products, FeO and CO2, are each stable compounds that can be accrued and separated from every other.

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