Question

What happens when XeF4 reacts with SbF5? Write the complete equation for the reaction

Answer 1

Answer:

XeF4 + SbF5 -> [XeF3]⁺ [SbF6]⁻

Explanation:

Xenon fluorides react with fluoride ion acceptors to form cationic species.

Answer 2

When $XeF_{4}$ reacts with $SbF_{5}$ then the reaction equation is as follows.

      $XeF_{4} + SbF_{5} \rightarrow [XeF_{3}]^{+}[SbF_{6}]^{-}$

Explanation:

According to Lewis, acids are the species which readily accept electrons. For example, $SbF_{5}$ acts as a Lewis acid.

The chemical reaction between $XeF_{4}$ and $SbF_{5}$ is as follows.

       $XeF_{4} + SbF_{5} \rightarrow [XeF_{3}]^{+}[SbF_{6}]^{-}$

In this reaction, antimony pentafluoride accepts electrons from xenon fluoride and hence, it forms antimony hexafluoride ion and xenon trifluoride ion.

Learn more about Lewis acid and base:

https://brainly.in/question/1897947

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