Physics, asked by hsjsjsba, 11 months ago

what horizontal acceleration should be provided to the wedge so that the block of mass m placed on the wedge to fall freely ? ​

Answers

Answered by Anonymous
3

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for free fall, normal reaction should be zero.

n = 0

for equilibrium perpendicular to the wedge,

0 + ma \sin \alpha  = mgcos \alpha

 =  > a =  \frac{g}{tan \alpha }

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