Physics, asked by om124556, 10 months ago

What horsepower engine is required to lift 18.24 quintals of coal per minute from amine of 50m deep?(take g=10m/s²)

Answers

Answered by rp2911mailbox31
0

Answer:

784 kw hour horsepower

Answered by muscardinus
3

The power required to lift 18.24 quintals of coal per minute from a mine of 50 m deep is 20.38 horsepower.

Explanation:

It is given that,

Mass of the coal, m = 18.24 quintals

1 quintal = 100 kg

Mass of the coal, m = 1824 kg

Time, t = 1 min = 60 s

Depth, d = 50 m

We need to find the power required to lift 18.24 quintals of coal per minute from a mine of 50 m deep. it is given by :

P=\dfrac{mgh}{t}

P=\dfrac{1824\times 10\times 50}{60}

P = 15200 W

Since, 1 horsepower = 746 watts

⇒ P = 20.38 horsepower

So, the power required to lift 18.24 quintals of coal per minute from a mine of 50 m deep is 20.38 horsepower. Hence, this is the required solution.

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