Math, asked by sasikalaprakash82, 7 months ago

what hould be added to 9 2/3 to get 19?

Answers

Answered by xSoyaibImtiazAhmedx
1

Step-by-step explanation:

\setlength{\unitlength}{0.5 cm}\begin{picture}(12,4)\thicklines\put(1,3){$.$}\put(5.5,5.5){$A$}\put(11.1,5.8){$B$}\put(11.08,8.9){$C$}\put(5.35,8.5){$D$}\put(3.45,10.15){$E$}\put(3.4,7.15){$F$}\put(9.14,10.235){$H$}\put(9.14,7.3){$G$}\put(3.3,6.3){$5\:cm$}\put(7.75,6.2){$7\:cm$}\put(11.1,7.5){$3\:cm$}\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}

\setlength{\unitlength}{1 cm}\begin{picture}(12,6)\thicklines\put(7.5,7.5){\circle{4}}\put(7.5,7.5){\line(1,0){0.70}}\put(4.2,8.5){$.$}\put(7.2,7.6){$10\:cm$}\end{picture}

\setlength{\unitlength}{0.9cm}\begin{picture}(12,6)\thicklines\put(2,4){\circle{1}}\put(4,4){\circle{1}}\put(6,4){\circle{1}}\put(8,4){\circle{1}}\put(2.14,4.1){$r$}\put(2,4){\line(1,0){0.47}}\put(4.14,4.1){$r$}\put(4,4){\line(1,0){0.47}}\put(6.14,4.1){$r$}\put(6,4){\line(1,0){0.47}}\put(8.14,4.1){$r$}\put(8,4){\line(1,0){0.47}}\end{picture}

Answered by eragaba07
1

Answer:

-35/3

Step-by-step explanation:

92/3 +x =19

x= 19-92/3

x= 57-92/3

x= -35/3

so -35/3 should he added to 92/3 to get 19

hope you get it

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