Chemistry, asked by fdrexlo3, 1 day ago

What hydrogen like ion has the wave length difference between the first line of Balmer and Lyman series equal to 59.3 nm​

Answers

Answered by ananyagulabrana
0

Answer:

According to the given question we have to find that in hydrogen-like ion has the wavelength difference between the first lines of Balmer and Lyman series equal to \[59.3nm{\text{ }}\left( {{R_H} = {\text{ }}109678cm^{- 1}} \right)\]. Hence, Hydrogen-like species is \[L{i^{2 + }}\].

Explanation:

Answered by MagicaIPrince
1

Answer:

According to the given question we have to find that in hydrogen-like ion has the wavelength difference between the first lines of Balmer and Lyman series equal to \[59.3nm{\text{ }}\left( {{R_H} = {\text{ }}109678cm^{- 1}} \right)\]. Hence, Hydrogen-like species is \[L{i^{2 + }}\].

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