what identity is used to evaluate[m+3][m+2]
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Answer:
(x - a) (x - b) = x2 – x (a + b) + ab
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Answer:
m(m+2) + 3(m+2)
m*2 + 2m + 3m + 6
m*2 + 5m +6
m*2 + (6m-m) + 6
m*2+ 6m - m + 6
m(m+6)-1(m+6)
(m-1)(m+6)
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