What if the oxidation state of Fe in (Fe (CN) 6) 4- ?
What is the oxidation no of CN?
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Answered by
9
The oxidation number of Fe in K4Fe(CN)6 can be calculated as follows,
4(+1) + x + 6(-1) = 0
Hence x = +2
4(+1) + x + 6(-1) = 0
Hence x = +2
Answered by
5
Answer:
X+6(-1)=-4
X-6 =-4
X=-4+6
X=2
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