What if the sum of all natural numbers from 1 to 100
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Gauss noticed that if he was to split the numbers into two groups (1 to 50 and 51 to 100), he could add them together vertically to get a sum of 101. Gauss realized then that his final total would be 50(101) = 5050. ... where a is the first term, d is the difference between terms, and n is the number of terms.
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a = 1
d = 1
an = 100
n = 100
Sn = n/2 ( a + an)
50 × 101
= 5050
d = 1
an = 100
n = 100
Sn = n/2 ( a + an)
50 × 101
= 5050
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