Question

what if the value of √162+√108 /√72+√48?

Answer 1

Hello friend,
√162=9√2
√108=6√3
√72=6√2
√48=4√3
√162+√108+√72+√48
=9√2+6√3+6√2+4√3
=15√2+10√3
=5(3√2+2√3)
hope it helps.

Answer 2

Answer:

Step-by-step explanation:

by doing prime factorization you can get the factors easily

root162 =

root( 2 × 3 × 3 × 3 × 3 ) = 9root2

root108 =

root( 2 × 2 × 3 × 3 × 3) = 6root3

root72 =

root(2 × 2 × 2 × 3 × 3) = 6root2

root48 =

root(2 × 2 × 2 × 3 × 2 ) = 4root3

( root162 + root108)/(root72 + root48)

= ( 9root2 + 6root3)/(6rot2 + 4root3)

= 3( 3root2 + 2root3)/2(3root2 + 2root3)

= 3/2