Question

What iis mean by Predipct the deducting agent and oxidising agent in this reaction
SO2+2H2S-2H2O+35

Answer 1

Answer:

Well, the oxidizing agent is the beast that accept electrons, i.e. it is the species that is reduced…

[math]\underbrace{SO_{2}(g)+4H^{+} + 4e^{-} \rightarrow S(s) +2H_{2}O(l)}_\text{Reduction half-equation}[/math]

And thus sulfur dioxide is the OXIDIZING agent…

And hydrogen sulfide is oxidized to sulfur… and thus sulfide is the reducing agent…

[math]\underbrace{H_{2}S(g)\rightarrow S(s) +2H^{+}+ 2e^{-} }_\text{Oxidation half-equation}[/math]

And we add the former to TWO of the latter…

[math]SO_{2}(g)+2H_{2}S(g)+4H^{+} + 4e^{-} \rightarrow 3S(s) +4H^{+}+ 4e^{-} +2H_{2}O(l)[/math]

To give….

[math]SO_{2}(g)+2H_{2}S(g) \rightarrow 3S(s)+2H_{2}O(l)[/math]

This is a so-called [math]\text{comproportionation reaction}[/math]

Explanation:

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