Question

What is 0∫π​cosxdx ?​

Answer 1

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Answer 2

HELLO,

GIVEN:- $\bold{\int\limits_0^\pi cosx\,dx}$

we integration of cos.dx = sinx

Therefore, $\bold{\int\limits_0^\pi cos\,dx = [sinx]_0^\pi}0∫πcosdx=[sinx]$

$\bold{\implies sin\pi - sin0}$

$\bold{\implies 0 - 0 = 0 }$