Question

what is (1+1)^2 =?,plz do it fast

Answer 1

Answer:

Let's break it down

Case 1:if it's eleven/two

Then

(1/2) of (11/2)=(1×11)/(2×2)=11/4

Case 2:if it is a mixed fraction

Then

1 1/2=1+(1/2)=(2+1)/2=3/2

Now,

1/2 of 3/2=(1/2)×(3/2)=(3×1)/(2×2)=3/4

Answer 2

$\mathfrak{dear\:user}$

$\mathfrak{question-(1+1)^2=? }$

$\mathfrak{here\:is\:the\:solution}$

$\mathbb{ANSWER}$

$(1+1)^2$

$(1+1)^2 =(2)^2$

$2^2=4$

$OR$

$(1+1)^2=1^2+1^2+2 \times 1 \times 1$

$1+1+2=4$

$\boxed{\therefore (1+1)^2=4 }$

$FORMULA \:USED=(a+b)^2 =a^2+b^2+2ab$

$\mathbb{EXTRA\;INFORMATION}$

$\boxed{\begin{minipage}{7cm}\boxed{\bigstar\:\:\textbf{\textsf{Algebric\:Identity}}\:\bigstar}\\\\1)\bf\:(A+B)^{2} = A^{2} + 2AB + B^{2}\\\\2)\sf\: (A-B)^{2} = A^{2} - 2AB + B^{2}\\\\3)\bf\: A^{2} - B^{2} = (A+B)(A-B)\\\\4)\sf\: (A+B)^{2} = (A-B)^{2} + 4AB\\\\5)\bf\: (A-B)^{2} = (A+B)^{2} - 4AB\\\\6)\sf\: (A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}\\\\7)\bf\:(A-B)^{3} = A^{3} - 3AB(A-B) + B^{3}\\\\8)\sf\: A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})\\\\\end{minipage}}$

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