Question

What is 1+2+3+4+5... to 100?

Answer 1

Answer:

5050

Step-by-step explanation:

sum of first n narural numbers = n(n+1)/2

Here, n=100

So, 1+2+3+4+5... to 100 is

n(n+1)/2 = 100(100+1)/2

= 100(101)/2

= 50(101)

= 5050