Question

what is 1/2*5/8 and 123/456 lowest term
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Answer 1

Step-by-step explanation:

vhjAnswer

Total resistance of this circuit will be = 13.22 ohm

Given :-

Two resistance 5 ohm & 4 ohm connect in parallel .

Other two resistance 8 ohm & 3 ohm connect with circuit in series .

Find :-

Total resistance in circuit

Step - by - Step - Explanation

Assume that,

Resistance A & B are connected in parallel , and C & D connected in series.

Where,

A = 5 ohm

B = 4 ohm

C = 8 ohm

D = 3 ohm

Using Formula

Total Resistance when, resister connect in parallel ,

\small{\boxed{\boxed{\tt{\red{\:\frac{1}{R_{t}}\:=\:\frac{1}{R_{1}}+\frac{1}{R_{2}}}}}}}

R

t

1

=

R

1

1

+

R

2

1

Total Resistance when, resister connect in Series.

\small{\boxed{\boxed{\tt{\red{\:R_{t'}\:=\:R_{1}+\:R_{2}}}}}}

R

t

′

=R

1

+R

2

When, A & B connect in parallel,

➡1/Rt = 1/5 + 1/4

➡1/Rt = (5+4)/20

➡1/Rt = 9/20

Or,

➡Rt = 20/9

➡Rt = 2.22 ohm

____________________

When, C & D connect in series,

➡Rt = 8 + 3

➡Rt' = 11 ohm

___________________

But, Now Rt & Rt' also connected in series in this circuit.

So, Total resistance be,

➡ R = Rt + Rt'

➡R = 2.22 + 11

➡R = 13.22 ohm

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