Question

what is -1/2x+3=1/3x-2 .find the value of x

Answer 1

Answer:

$\huge\color{blue}{\colorbox{red}{\colorbox{white}{answer}}} \\ \frac{ - 1}{2}x + 3 = \frac{1}{3} x - 2 \\ \frac{ - x + 6}{2} = \frac{x - 6}{3} \\ 3( - x + 6) = 2(x - 6) \\ - 3x + 18 = 2x - 12$

$x = \frac{6}{5}$

HOPE HELPFUL

Answer 2

Answer:

∴ The required value of $x$ in given expression $\frac{-1}{2x+3} =\frac{1}{3x-2}$ is $-\frac{1}{5}$.  

Step-by-step explanation:

• In context with question asked,
• We have to find the value of $x$.
• The given expression is,

      $\frac{-1}{2x+3} =\frac{1}{3x-2}$

• To find the value of $x$, by cross multiplication, we get

    ∴ $-1(3x-2)=1(2x+3)$

• Opening the brackets, we get

       ∴ $-3x+2=2x+3$

• Collecting the terms with variable at one side and constant terms at another side, we get

        ∴ $-3x-2x=3-2$

               ∴ $-5x=1$

                   ∴ $x=\frac{1}{-5}$  

• ∴ The required value of $x$ in given expression $\frac{-1}{2x+3} =\frac{1}{3x-2}$ is $-\frac{1}{5}$.