Question

what is 1+cos thetha
and 1+sin thetha​

Answer 1

Answer:

Step-by-step explanation:

We have ,

f(x):1+cosx  

Since,  

cos2x=cos2(x)−sin2(x)  

=> cos(x+x)=cosx.cosx−sinx.sinx  

cos2x=cos2(x)−(1−cos2(x))  

cos2x=2cos2(x)−1  

Thus,  

2cos2(x)=1+cos2x  

Similarly,  

1+cosx=2cos2(x/2)  

Thank you..!!