what is (1-tanA/1-cotA)square and how
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(1-tanA/1-cotA)^2
=(1+tan^2A-2tanA)/(1+cot^2-2cotA)
=(sec^2A-2tanA)/(cosec^2A-2cosA/sinA)
=(sec^2A-2*sinA/cos A)/(cosec^2A-2cosA/sinA)
=(1/cos^2A-2sinA/cosA)/(1/sin^2A-2cosA/sinA)
=[(1-2sinAcosA)/cos^2A]/[(1-2cosAsinA)sin^2A]
=(1-2sinAcosA)/cos^2A*sin^2A/(1-2sinAcosA)
=sin^2A/cos^2A
=tan^2A
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