Question

WHAT IS 10*80*90*69 of the following​

Answer 1

Answer:

Median = 92.5

Step-by-step explanation:

The given frequency distribution is ;

CI f Revised CI Cumulative frequency,F (Less than type)

60-69 5 59.5-69.5 5

70-79 15 69.5-79.5 20

80-89 20 79.5-89.5 40

90-99 30 89.5-99.5 70

100-109 20 99.5-109.5 90

110-119 8 109.5-119.5 92

\sum f∑f = 98

Here, we have revised Class Interval(CI) because in the original CI upper limit of previous class is not same with the lower limit of next class. So, for doing this we have subtracted 0.5 from lower limit and added 0.5 to the upper limit.

Now, the median formula is given by = x_L + \frac{\frac{N}{2} - F_L }{f_m} * cx

L

+

f

m

2

N

−F

L

∗c

where, x_Lx

L

= Lower limit of median class

N = Total Frequency

f_mf

m

= frequency of median class

F_LF

L

= cumulative frequency of just above the median class frequency

c = width of median class

So, First we calculate \frac{N}{2}

2

N

= \frac{98}{2}

2

98

= 49 .

Here, the cumulative frequency just greater than or equal to 49 is 70.

Hence, the median class is 89.5-99.5 .

And x_Lx

L

= 89.5

N = 98

f_mf

m

= 30

F_LF

L

= 40

c = 10

Putting all these values in median formula we get,

Median = 89.5 + \frac{\frac{98}{2}-40 }{30} * 1089.5+

30

2

98

−40

∗10 = 92.5 .

Other links for similar questions;

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Explanation:

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Answer 2

$\huge \bold \pink{question}$

WHAT IS 10 × 80× 90 × 69 of the following.

$\huge \bold \green{solution}$

→ 10 × 80 × 90 × 69 = 4968000

$\huge \bold \orange{answer}$

4968000

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$\red {i \: hope \: it \: will \: help \: you}$

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