Math, asked by catinthehat123454, 4 months ago

what is (2/3)^3*(2/3)^6=(4/9)^2k-3
pls answer

Answers

Answered by rupesh031978
18

Answer:

(4/9)^2k-3= (2/3)^3×(2/3)^6

(2/3)^2(2k-3)= (2/3)^(3+6)

(2/3)^4k-6= (2/3)^9

4k-6=9

4k= 9+6

k= 15/4

Answered by shobhathrilok1
0

Hope it helps yoplease mark as brainlieat

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