Math, asked by firdausmahek, 5 months ago

what is 2(3y-2)-4(2y-5)=9

Answers

Answered by akruthika030660
1

Answer:

2(3y-2)-4(2y-5)=9

6y-4-8y+20=9

-2y-4+20=9

-2y+20=9+4

-2y+20=13

-2y=13-20

-2y=-7

y=-7/-2

y=7/2

Step-by-step explanation:

hope it helps....

Answered by KOTTURSRIYA
1

Answer:

7by2

Step-by-step explanation:

Distribute

2(3y-2)-4(2y-5)=9

6y-4-4(2y-5)=9

6y-4-4(2y-5)=9

6y-4-8y+20=9

Add the numbers

6y-4-8y+20=9

6y+16-8y=9

Combine like terms

6y+16-8y=9

-2y+16=9

Subtract 16 by both sides of the equation

-2y-16=9

2y+16-16=9-16

Simplify

  • Subtract the numbers

*

*

*

  • Subtract the numbers

-2y=-7

Divide both sides of the equation by the same term

-2y=-7

-2y=-7

-2y=-2

Simplify

  • Cancel terms that are in both the numerator and denominator
  • Divide the numbers

y=7by2

y=7by2

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