what is 2a⁴+a⁴-3a⁴+6a ???????
Answers
Answer:
Hello mate ✌️♻️..
Step-by-step explanation:
6a⁵ - a⁴ + 4a³ - 5a² - a - 15 = ( 2a² - a + 3 ) (3a³ + a² - 2a -5)
Step-by-step explanation:
show by the division method that (2a^2-a+3) is a factor of (6a^5-a^4+4a^3-5a^2-a-15)
3a³ + a² - 2a -5
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2a² - a + 3 _| 6a⁵ - a⁴ + 4a³ - 5a² - a - 15 |_
6a⁵ -3a⁴ + 9a³
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2a⁴ - 5a³ - 5a² - a - 15
2a⁴ - a³ + 3a²
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-4a³ - 8a² - a - 15
-4a³ + 2a² -6a
________________________
-10a² + 5a - 15
-10a² + 5a - 15
_________________
0
______________________
6a⁵ - a⁴ + 4a³ - 5a² - a - 15 = ( 2a² - a + 3 ) (3a³ + a² - 2a -5)
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Answer:
6a
Step-by-step explanation:
2a⁴+a⁴-3a⁴+6a
First we see that 2a⁴,a⁴ and -3a⁴ are like as they have the same variable(and 6a wont be considered in this group as the other three terms have the power of 'a' as 4 whereas 6a has the power of 'a' as 1)
So we can add or subtract like terms, hence,
=> 3a⁴ - 3a⁴ + 6a (2a⁴ + a⁴ = 3a⁴)
=> 6a (as 3a⁴ - 3a⁴ = 0)
Hope it helps amd have a good day:))))))