What is 2sin (2x+y) cos (x-2y)??
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SOLUTION 1 : Begin with x3 + y3 = 4 . Differentiate both sides of the equation, getting
D ( x3 + y3 ) = D ( 4 ) ,
D ( x3 ) + D ( y3 ) = D ( 4 ) ,
(Remember to use the chain rule on D ( y3 ) .)
3x2 + 3y2 y' = 0 ,
so that (Now solve for y' .)
3y2 y' = - 3x2 ,
and
D ( x3 + y3 ) = D ( 4 ) ,
D ( x3 ) + D ( y3 ) = D ( 4 ) ,
(Remember to use the chain rule on D ( y3 ) .)
3x2 + 3y2 y' = 0 ,
so that (Now solve for y' .)
3y2 y' = - 3x2 ,
and
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I think that's not correct
Answered by
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2.sin(2x+y).cos (x-2y)
=sin (2x+y+x-2y) [sin(A+B)+sin(A-B) = 2 sinA cosB ]
=sin (3x-y)
HOPE IT HELPS!!
=sin (2x+y+x-2y) [sin(A+B)+sin(A-B) = 2 sinA cosB ]
=sin (3x-y)
HOPE IT HELPS!!
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