Question

What is ∫2x3−3x2−4x−3−6x2+3x−4dx?

Answer 1

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∫2×3-3×2-4x-3-6×2+3x-4dx

= ∫(2×3-3×2-4x-3-6×2+3x-4)dx

= ∫(6-6-4x-3-12+3x-4)dx

= ∫(19-x)dx

= ∫19dx - ∫xdx + c

= 19x - x²/2 + c

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