Question

what is 438 048 when expressed as a product of its prime factor please help me

Answer 1

Step-by-step explanation:

Given: 438048

To find: Prime factorisation

Solution:

To express any number as a product of prime factorisation,divide the number by prime factors one after another.

The whole process is shown below:

$\begin{array}{r|1}2&438048\\\cline{2-2}2&219024\\\cline{2-2}2&109512\\\cline{2-2}2&54756\\\cline{2-2}2&27378\\\cline{2-2}3&13689\\\cline{2-2}3&4563\\\cline{2-2}3&1521\\\cline{2-2}3&507\\\cline{2-2}13&169\\\cline{2-2}13&13\\\cline{2-2}&1\end{array}$

Thus,

$438048 = 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times13 \times 13$

Final answer:

Product of prime factors can also be written as

$\bold{438048=2^5\times3^4\times13^2}$

Hope it helps you.

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