What is 50000 evolution to travel distance of 121 kilometre what is the diameter of the wheel of the car?
Answers
Answered by
2
Revolution=50000, D=121km=12100000cm ..
In 1 revolution distance= 12100000/50000=242 cm.
Therefore, Circumference of wheel=
2πr =)
2×22/7×r= 242
r= 242×7/2×22
r=77/2 cm
D= 2r = 2×77/2 =) 77cm.
Hope it Helps.
Mark as Brainliest ...!!
In 1 revolution distance= 12100000/50000=242 cm.
Therefore, Circumference of wheel=
2πr =)
2×22/7×r= 242
r= 242×7/2×22
r=77/2 cm
D= 2r = 2×77/2 =) 77cm.
Hope it Helps.
Mark as Brainliest ...!!
Answered by
0
The answer is given below :
Let the diameter of the wheel be d.
Then, perimeter is = πd m
In one evolution, the wheel travels πd m
In 50000 evolutions, the wheel will travel
= 50000πd m, which is equal to the total distance 121 km = 121000 m
=> 50000πd = 121000
=> d = 121000/(50000π)
=> d = 0.77 (approximately)
So, tye diameter of the wheel of the car is 0.77 m.
Thank you for your question.
Let the diameter of the wheel be d.
Then, perimeter is = πd m
In one evolution, the wheel travels πd m
In 50000 evolutions, the wheel will travel
= 50000πd m, which is equal to the total distance 121 km = 121000 m
=> 50000πd = 121000
=> d = 121000/(50000π)
=> d = 0.77 (approximately)
So, tye diameter of the wheel of the car is 0.77 m.
Thank you for your question.
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