Math, asked by Rajatpratao3518, 1 year ago

What is 50000 evolution to travel distance of 121 kilometre what is the diameter of the wheel of the car?

Answers

Answered by Khushi0511
2
Revolution=50000, D=121km=12100000cm ..
In 1 revolution distance= 12100000/50000=242 cm.

Therefore, Circumference of wheel=
2πr =)
2×22/7×r= 242
r= 242×7/2×22
r=77/2 cm
D= 2r = 2×77/2 =) 77cm.


Hope it Helps.
Mark as Brainliest ...!!
Answered by Swarup1998
0
The answer is given below :

Let the diameter of the wheel be d.

Then, perimeter is = πd m

In one evolution, the wheel travels πd m

In 50000 evolutions, the wheel will travel

= 50000πd m, which is equal to the total distance 121 km = 121000 m

=> 50000πd = 121000

=> d = 121000/(50000π)

=> d = 0.77 (approximately)

So, tye diameter of the wheel of the car is 0.77 m.

Thank you for your question.
Similar questions