Question

What is 6x square-4xy-10y square divide by 2x+2y

Answer 1

Given:

The two expressions $6x^{2}-4xy-10y^{2}$ and $2x+2y$.

To find:

We have to divide $6x^{2}-4xy-10y^{2}$ by $2x+2y$.

Step-by-step explanation:

Now, $6x^{2}-4xy-10y^{2}$

$=2(3x^{2}-2xy-5y^{2}$

$=2(3x^{2}-5xy+3xy-5y^{2})$

$=2\{x(3x-5y)+y(3x-5y)\}$

$=2(3x-5y)(x+y)$

$=(3x-5y)(2x+2y)$

This shows that when $6x^{2}-4xy-10y^{2}$ is divided by $2x+2y$, the quotient is $(3x-5y)$.

Answer:

The required quotient is $3x-5y$.