Question

what is (8-x) (8+x) ? ​

Answer 1

By i

using identity (a+b) (a-b)= a^2-b^2

hence

(8-x)(8+x)= 64-x^2.......

Answer 2

(8-x) (8+x)

Multiply the both term

→ 64 + 8x -8x -x² = 0

→ 64 +(-x²) = 0

→ 64 -x² = 0

→ x² -64

→ (x² -8²)

Here the identity use

→ ( a² - b² ) = ( a - b ) ( a + b )

Additional Information !!

Some More identities!!

• (a + b)² = a² + b² +2ab

• ( a - b )² = a² + b² -2ab

• ( a² - b² ) = ( a - b ) ( a + b )

• ( a +b +c)² = (a² + b² + c²) + 2(ab + bc +ca)

• (a + b)³ = a³ + b³ + 3ab(a+b)

• (a-b)³ = a³ - b³ -3ab(a-b)

• ( a³ + b³) = (a+b) (a²-ab +b²)

• (a³ - b³) = (a -b) (a² + ab + b²)