Question

What is 8x-(6+y)
3/4w+ x^2
y^2-0.5w
w/4+3(x+y)

if w=4 x=5 y=6

Answer 1

Given:$w=4,x=5,y=6$.

To find: The value of the given equation after putting the values.

Solution:

The value of the given equation will be calculated after substituting the values of the variables.

$a) 8x-(6+y)\\=8*5-(6+6)\\=40-12\\=28$

$b) \frac{3}{4}w+x^{2} \\=\frac{3}{4}*4+5^2\\=3+25\\=28$

$c)y^2-0.5w\\=6^2-0.5*4\\=6*6-2\\=36-2\\=34$

$d)\frac{w}{4}+3(x+y)\\=\frac{4}{4}+3(5+6)\\=1+3*11\\=1+33\\=34$.

The value of the equations are 28,28,34, and 34 respectively.