Math, asked by omq, 20 days ago

what is 9999999999+20000000000000+1201201209392858

Answers

Answered by llAestheticKingll91
4

Answer:

\begin{gathered}\begin{gathered}\\ \sf\longmapsto \frac{100}{105x}(350)=\frac{100}{100x} \\ (340)\end{gathered}\end{gathered}⟼105x100(350)=100x100(340)</p><p></p><p> \\ \begin{gathered}\begin{gathered}\\ \sf\longmapsto \frac{20}{21x}×350=\frac{1}{x}×340\end{gathered}\end{gathered}⟼21x20×350=x1×340</p><p></p><p>\begin{gathered}\begin{gathered}\\ \sf\longmapsto \frac{20}{3x}×50=\frac{340}{x}\end{gathered}\end{gathered}⟼3x20×50=x340</p><p></p><p>\begin{gathered}\begin{gathered}\\ \sf\longmapsto \frac{1000}{3x}=\frac{340}{x}\end{gathered}\end{gathered}⟼3x1000=x340</p><p></p><p>\begin{gathered}\begin{gathered}\\ \sf\longmapsto 1000x=1020x\end{gathered}\end{gathered}⟼1000x=1020x</p><p></p><p>\begin{gathered}\begin{gathered}\\ \sf\longmapsto 1000x-1020x=0\end{gathered}\end{gathered}⟼1000x−1020x=0</p><p></p><p>\begin{gathered}\begin{gathered}\\ \sf\longmapsto -20x=0\end{gathered}\end{gathered}⟼−20x=0</p><p></p><p>\begin{gathered}\begin{gathered}\\ \sf\longmapsto x=0\end{gathered}\end{gathered}⟼x=0</p><p></p><p>\begin{gathered}\begin{gathered}\\ \sf\longmapsto x∈Ø\end{gathered}\end{gathered}⟼x∈Ø

Answered by βαbγGυrl
1

Answer:

  • 9999999999+20000000000000+1201201209392858 = 1.22121121E15

Similar questions