Question

what is a area of a rhombus with side 10 cm and lenth of the diagonal 16 cm ?​

Answer 1

Answer:

Formula = D1 x D2 \ 2

So, 1O x 16 \2 = 8O

Area = 8Ocm² ( Ans )

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Answer 2

Before, finding the answer. Let's find out how we can find the answer.

• In this question, we are asked to find the Area of the Rhombus.
• So, to find the Area, we must use the formula of :

$\boxed{ \sf Area \: of \: Rhombus = Side \times Diagonal \times \frac{1}{2} }$

• Where we have to multiply the Side and Diagonal first. And then, we have to divide it 2.

______________________

Given :

• Side = 10 cm
• Diagonal = 16 cm

To find :

• Area of the Rhombus

Solution :

We know that,

${ \sf Area \: of \: Rhombus = Side \times Diagonal \times \dfrac{1}{2} }$

                          $\sf = 10 \times 16 \times \dfrac{1}{2} }$

                          $\sf = 160 \times \dfrac{1}{2} }$

                          $\sf = \dfrac{1 \times 160}{2} }$

                          $\sf = \dfrac{160}{2} }$

                          $\sf = 80 \: cm^2$

Therefore, the Area of the Rhombus is 80 cm².