Question

what is a average of 10 to 19 natural numbers​

Answer 1

answer

average =

$\frac{sum \: of \: the \: numbers \: from \: 10 \: to \: 19}{number \: of \: all \: the \: digits}$

Step-by-step explanation:

$\frac{11 + 12 + 13 + 14 + 15 + 16 + 18 + 19}{9}$

$\frac{145}{9}$

average is 16.1111...... or you cha wrote in round off form that is 16

hope it helps

Answer 2

Answer:

average =

10+11+12+13+14+15+16+17+18+19 =145

10 to 19 is 10+9=19

so you have to divided

145÷10 = 14.5,

please give me brain list