Math, asked by Batoolanjum, 3 months ago

What is A+B+B+B+80+90=100? ​

Answers

Answered by johnjoshua0210
0

Answer:

Add the numbers

+

+

+

8

0

+

9

0

=

1

0

0

b+b+b+{\color{#c92786}{80}}+{\color{#c92786}{90}}=100

b+b+b+80+90=100

+

+

+

1

7

0

=

1

0

0

b+b+b+{\color{#c92786}{170}}=100

b+b+b+170=100

2

Combine like terms

+

+

+

1

7

0

=

1

0

0

{\color{#c92786}{b}}+{\color{#c92786}{b}}+{\color{#c92786}{b}}+170=100

b+b+b+170=100

3

+

1

7

0

=

1

0

0

{\color{#c92786}{3b}}+170=100

3b+170=100

3

Subtract

1

7

0

170

170

from both sides of the equation

3

+

1

7

0

=

1

0

0

3b+170=100

3b+170=100

3

+

1

7

0

1

7

0

=

1

0

0

1

7

0

3b+170{\color{#c92786}{-170}}=100{\color{#c92786}{-170}}

3b+170−170=100−170

4

Simplify

Subtract the numbers

Subtract the numbers

3

=

7

0

3b=-70

3b=−70

5

Divide both sides of the equation by the same term

3

=

7

0

3b=-70

3b=−70

3

3

=

7

0

3

\frac{3b}{{\color{#c92786}{3}}}=\frac{-70}{{\color{#c92786}{3}}}

33b=3−70

6

Simplify

Cancel terms that are in both the numerator and denominator

=

7

0

3

Answered by sangeetaprasad31
1

Answer:

Akkad Bakkad Bambe bo 80+90=100 XD....

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