Math, asked by tgsr123, 1 month ago

what is a+b+c+d+1×23499÷23=​

Answers

Answered by ruchiverma19032007
2

Answer:

the answer is 942 . 50

give me thank

Answered by akshayaakumar1982
0

Answer: it’s a pleasure to help you friend..

Step-by-step explanation:

As “a,b,c,d” are variables, we just have to find the constant terms.

The constant terms in “ a+b+c+d+1×23499÷23 “ are “ 1, 23499, and 23.

So let’s find the value of 1 × 23499 ÷ 23 first.

⇒ 1 × 23499 ÷ 23 = 23499 ÷ 23

= 1021.69

∴ The value of “1 × 23499 ÷ 23” is “1021.69”.

As we found the value of it, we can replace the sum from

“a + b + c + d + 1 × 23499 ÷ 23” to “a + b + c + d + 1021.69 “

⇒ a + b + c + d + 1 × 23499 ÷ 23 = a + b + c + d + 1021.69

⇒ LHS = RHS.

∴ The answer is “a + b + c + d + 1021.69”.

Hope it’s useful friend..

Good luck and have a great day..

Stay safe and happy !!

Keep rocking !!

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