what is a+b+c+d+1×23499÷23=
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Answer:
the answer is 942 . 50
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Answered by
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Answer: it’s a pleasure to help you friend..
Step-by-step explanation:
As “a,b,c,d” are variables, we just have to find the constant terms.
The constant terms in “ a+b+c+d+1×23499÷23 “ are “ 1, 23499, and 23.
So let’s find the value of 1 × 23499 ÷ 23 first.
⇒ 1 × 23499 ÷ 23 = 23499 ÷ 23
= 1021.69
∴ The value of “1 × 23499 ÷ 23” is “1021.69”.
As we found the value of it, we can replace the sum from
“a + b + c + d + 1 × 23499 ÷ 23” to “a + b + c + d + 1021.69 “
⇒ a + b + c + d + 1 × 23499 ÷ 23 = a + b + c + d + 1021.69
⇒ LHS = RHS.
∴ The answer is “a + b + c + d + 1021.69”.
Hope it’s useful friend..
Good luck and have a great day..
Stay safe and happy !!
Keep rocking !!
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