Question

what is a conical pendulum show that its time period is given by 2π√lcosΦ/g where l is length of stringΦis the angle that makes with the vertical and g is the acceleration due to gravity ​

Answer 1

Solution.

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = mac

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = macThe expression Fnet = mac is a vector equation so we can write it as two component equations: Fnet,x = mac and Fnet,y = 0. (The ball is not accelerating vertically.)

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = macThe expression Fnet = mac is a vector equation so we can write it as two component equations: Fnet,x = mac and Fnet,y = 0. (The ball is not accelerating vertically.)In the x-direction, there is only FT,x. Thus,

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = macThe expression Fnet = mac is a vector equation so we can write it as two component equations: Fnet,x = mac and Fnet,y = 0. (The ball is not accelerating vertically.)In the x-direction, there is only FT,x. Thus,FT,x = mac

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = macThe expression Fnet = mac is a vector equation so we can write it as two component equations: Fnet,x = mac and Fnet,y = 0. (The ball is not accelerating vertically.)In the x-direction, there is only FT,x. Thus,FT,x = macor

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = macThe expression Fnet = mac is a vector equation so we can write it as two component equations: Fnet,x = mac and Fnet,y = 0. (The ball is not accelerating vertically.)In the x-direction, there is only FT,x. Thus,FT,x = macorFT∙sin(α) = mac    (1).

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = macThe expression Fnet = mac is a vector equation so we can write it as two component equations: Fnet,x = mac and Fnet,y = 0. (The ball is not accelerating vertically.)In the x-direction, there is only FT,x. Thus,FT,x = macorFT∙sin(α) = mac    (1).The magnitude of the centripetal acceleration is given by

Solution.According to Newton’s Second Law for uniform circular motion, the net force acting on the ball equals mac.Fnet = macThe expression Fnet = mac is a vector equation so we can write it as two component equations: Fnet,x = mac and Fnet,y = 0. (The ball is not accelerating vertically.)In the x-direction, there is only FT,x. Thus,FT,x = macorFT∙sin(α) = mac    (1).The magnitude of the centripetal acceleration is given byac=ω2r    (2).