Question

what is a direction and acceleration of an object at the highest point of projectile​

Answer 1

Answer:

Given:

A projectile has been fired from the ground.

To find:

Direction of velocity and acceleration of the projectile at the highest point.

Concept:

Let us consider that the projectile has been fired at an angle of θ with the horizontal. And let initial velocity be "v".

Hence we can divide the velocity into 2 components.

• along x axis = v cos(θ)
• along y axis = v sin(θ)

At the highest point, the projectile has only x axis velocity . The direction of the velocity vector is parallel to the x-axis.

At the same time, the projectile only has downwards gravitational acceleration ( g).

The direction of the acceleration vector is vertically downwards (parallel to the y axis).

Answer 2

Answer:

Let a body is projected at an angle $\alpha$ with initial velocity $u$.

Now, the projectile motion lies in XY coordinate plane.

Therefore, the components of velocity will lie on the X and Y axis.

Component of velocity will be,

• X component = $u \cos \alpha$
• Y component = $u \sin \alpha$

Now, at the highest point of the projectile,

• The Y component of velocity vector becomes zero.
• There is only X component of the velocity vector at the highest point.

Therefore, the direction of velocity vector will be only in X direction at the highest point.

Now, the acceleration in projectile acts vertically downwards in negative Y direction.

• The magnitude of the acceleration is $\sf{g\:m{s}^{-2}}$.
• Direction of acceleration is vertically downwards.