What is a distance find by a 3d falling body in 3sec
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Distance travelled can be found be the acceleration due to gravity.
If we have to find the distance travelled by a free falling body, we can use the formula,
s = distance = ut + (1/2) a t^2
where,
u is the initial velocity of the body, a is acceleration due to gravity and t is the time taken by the object
Given, t = 3 s
u = 0 m/s
g = a = 9.81 m/s^2
Therefore,
s = 0(t) + (1/2) 9.81 × 3 × 3
Hence the distance travelled by the free falling object in three seconds is 44.415 m.
-WonderGirl
If we have to find the distance travelled by a free falling body, we can use the formula,
s = distance = ut + (1/2) a t^2
where,
u is the initial velocity of the body, a is acceleration due to gravity and t is the time taken by the object
Given, t = 3 s
u = 0 m/s
g = a = 9.81 m/s^2
Therefore,
s = 0(t) + (1/2) 9.81 × 3 × 3
Hence the distance travelled by the free falling object in three seconds is 44.415 m.
-WonderGirl
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