Question

What is a equation of a line that passes through the point 4,6 and has a slope of -3?

Answer 1

Hey friend!
Equation passing through one point
y-y1 = m (x-x1)
Where given points (x,y)=(4,6)
m is slope =-3
Now y-6= -3(x-4)
y-6=-3x+12
3x+y-18=0
Which is required eqn

I hope it helps u

Answer 2

Here using it one point form ie (y-y1 ) =m (x-x1). Here y1 and x1 are coordinate of passing point so x1=4 & y1 =6 and m is the slope so m = - 3. Hence equation =y-6= - 3(x-4)=y-6= - 3x +12 =y+3x - 6 +12 ==y+3x +6==0. This is your equation