what is a least number by which 26244 has to divided to make them perfect cube
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36. Do prime factorisation of the number.
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hi friend
here's your answer looking for
26244= 2×2×3×3×3×3×3×3×3×3
So, 2×2×3×3 can not be represented in the form of triplet
so, 2×2×3×3 = 36 is a required number that should be divided by 26244 to make it perfect cube.
hope you are satisfied with my answer
From brainly star Amaytripathi19
here's your answer looking for
26244= 2×2×3×3×3×3×3×3×3×3
So, 2×2×3×3 can not be represented in the form of triplet
so, 2×2×3×3 = 36 is a required number that should be divided by 26244 to make it perfect cube.
hope you are satisfied with my answer
From brainly star Amaytripathi19
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