Question

What is a projectile? Obtain an expression for (i) maximum height and (ii) time of flight, when it is fired at an angle ϴ with the horizontal.

Answer 1

Answer:

sorry for not responding to do it

Answer 2

Answer:

H=u2sin2θg−u2sin2θ2g⇒H=u2sin2θ2g. Hence the expression for the maximum height. The time of ascent. The time taken by the body to reach the maximum height when projected vertically upwards. Let the time taken by the projectile to reach the maximum height = t.

Explanation:

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