Question

what is a right answer ???​

Answer 1

so inner curved surface area would be

$2πrh$

so the inner curved surface area would be

$2×\frac{22}{7}×14×21$

$2×22×2×21$

$=1848m^2$

now the outer curved surface area

$2×\frac{22}{7}×21×21$

$2×22×3×21$

$=2772m^2$

total area is

$1848m^2 + 2772m^2$

$=4620m^2$

so total cost would he

$4620m^2 × 25$

=115,500 rupees

Answer 2

Answer:

Step-by-step explanation: