Question

What is a root of following equation 4(2x-3)^2 - (2x-3) -14=0​

Answer 1

Answer:

5/2   or  5/8

Step-by-step explanation:

   Let 2x - 3 = a,

⇒ 4a^2 - a - 14 = 0

⇒ 4a^2 - (8 - 7)a - 14 = 0

⇒ 4a^2 - 8a + 7a - 14 = 0

⇒ 4a(a - 2) + 7(a - 2) = 0

⇒ (a - 2)(4a + 7) = 0

⇒ a = 2       or 4a + 7 = 0

⇒ a = 2       or  4a = - 7

        Substitute the value of a:

⇒ 2x - 3 = 2    or 4(2x-3) = -7

⇒ 2x = 2+3    or 8x - 12= - 7

⇒ x = 5/2       or  8x = 12 - 7

⇒ x = 5/2       or x = 5/8

Answer 2

Step-by-step explanation:

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