Question

what is a surface area of an open cubical box having each edge as 8 m

Answer 1

Sol'n:Edge (a) = 8m

Surface area of the box
= 5a²
= 5 × (8)²
= 5 × 64
= 320m²

[Note: The open box is opened in one side.]

Answer 2

Surface area of cube=6a²

where a is the side of cube.

Given edge =8cm

so: a=8

Surface area=6*(8cm)²

=6*64cm²

=384cm²

Surface area is 384cm²

Hope it helps you.